What is the effect on current If voltage in a circuit remains constant and the resistance increases? So doubling or tripling the resistance will cause the current to be one-half or one-third the original value. Any alteration in the voltage will result in the same alteration of the current. The current is directly proportional to the voltage and inversely proportional to the resistance. What happens to the current if the voltage stays the same but the resistance is doubled? so the resistance will remain constant if current is boubled through doubling the voltage supply. What happens to the resistance of a circuit when the current through it is doubled?Īnswer: If you are doubling the current, either you are doing if by increasing the voltage or by decreasing the resistance or by a combination of both. If the resistance is doubled by applying the constant potential difference the current becomes the half of the previous. When resistance is doubled at constant voltage current will be? 8 What happens when you increase the resistance of a wire?.7 What happens to the resistance of a diode when the voltage is exceeded?.6 What happens if you decrease the resistance in a circuit?.5 What happens to current if resistance increases?.4 What happens when resistance is increased?.3 What happens if the resistance is doubled?.2 What happens to the resistance of a circuit when the current through it is doubled?.1 When resistance is doubled at constant voltage current will be?.The instructor's method is meant to prepare you for more complicated problems. These problems are designed to be solved, and often without a calculator or complicated equations. See if there are symmetries or convenient ratios and other numbers. My advice is look at problems for a while. Voltage is V = IR = 6 amps x 8 ohms = 48 volts. Isn't that convenient? Therefore 6 amps flow through the 8 and 1.6 ohm resistors. What is the total current? The diagram says 30 amps. 4 portions to the 2.4 ohm and 1 to the 9.6 ohm. This means you can divide the total current into 5 equal portions. Isn't that convenient? So 4 times the current will flow through the 2.4 ohm as will flow through the 9.6 ohm combination. The 8 and 1.6 are in series and add up to 9.6 ohm.īy examination, you have 2.4 ohm in parallel with 9.6 ohms. The 2.4 ohm is in parallel with the 8 and the 1.6. You can keep this simple and logical, as is the case in many example problems. It's just one that fell out in this case. Your teacher's formula isn't an extensible formula. (Or use nodal analysis, if the circuit is more complex.) That's pretty much how most would approach it. Then work through the details for the branch itself to get the current. Normally, people do as some of the other answers suggest - work out the series and parallel resistances to a single value (if possible) and then figure out the voltage. This means I don't agree an answer suggesting, "Your professor has given the formula for a current divider." If you must use resistances in the current branching case like this, then you have to follow (6) above and DO NOT simply try and extend what your teacher did in some ignorant way. As you can see, using resistances isn't right off the bat intuitive. So, if you want to commit something to memory, go with the conductances approach. Don't forget that, either.Įquation (6) is a lot uglier than you might have imagined from your teacher's solution. So in one of your branches, this value is a sum. These resistances are the effective branch resistances. Keep in mind that in the above, each \$R_i\$ is not each of all your resistors, helter-skelter. First you find the voltage across the branches: Mathematically, it's pretty straightforward.
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